K&R C book - exercise 3.3

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I have an exercise in my ANSI C book:




3.3. Write a function expand(s1,s2) that expands shorthand notations like a-z in the string s1 into the equivalent complete list abc…xyz in
s2. Allow for letters of either case and digits, and be prepared to
handle cases like a-b-c and a-z0-9 and -a-z. Arrange that a leading or
trailing - is taken literally.




I have attempted to solve it and here's my code:



#include <stdio.h>
#include <string.h>
#define MAXLEN 100

void expand(char * s1, char * s2);

int main(void)
char s1 = "a-b-c";
char s2[MAXLEN];
expand(s1, s2);
printf("%sn", s2);
return 0;


void expand(char * s1, char * s2)
char prev = '';
char mid = '';
char next = '';
if (s1[0] == '-')
*s2 = *s1;
s1++, s2++;

while (*s1 != '')
if (next == '' && mid == '-')
*s2++ = mid;
else if (mid == '-')
if (prev < next)
for (char i = prev; i <= next; i++, s2++)
*s2 = i;
else
for (char i = prev; i >= next; i--, s2++)
*s2 = i;

prev = *s1;
s1++;
mid = *s1;
if (*s1 != '')
next = *(s1 + 1);

*s2 = *s1;



What do you think about this solution? Does it solve the exercise? Is it a good way to solve it?







share|improve this question





















  • Well, you are writing in ANSI C, not K&R C. Your title reads “K&R C book”?
    – JDługosz
    Jun 9 at 22:28










  • They are probably reffering to the second edition. K&R C is named after the C shown in "The C Programming Language". The second edition is modified to use ANSI C.
    – Peter
    Jun 23 at 21:45










  • This is a terrible exercise. I don't understand the instructions at all. Does "be prepared to handle cases like a-b-c" mean the result would be abbc? or abc? And what does "Arrange that a leading or trailing -is taken literally." mean? Is it intended that when part of the string is not a range, that you simply copy it?
    – user1118321
    Jul 10 at 4:42
















up vote
4
down vote

favorite












I have an exercise in my ANSI C book:




3.3. Write a function expand(s1,s2) that expands shorthand notations like a-z in the string s1 into the equivalent complete list abc…xyz in
s2. Allow for letters of either case and digits, and be prepared to
handle cases like a-b-c and a-z0-9 and -a-z. Arrange that a leading or
trailing - is taken literally.




I have attempted to solve it and here's my code:



#include <stdio.h>
#include <string.h>
#define MAXLEN 100

void expand(char * s1, char * s2);

int main(void)
char s1 = "a-b-c";
char s2[MAXLEN];
expand(s1, s2);
printf("%sn", s2);
return 0;


void expand(char * s1, char * s2)
char prev = '';
char mid = '';
char next = '';
if (s1[0] == '-')
*s2 = *s1;
s1++, s2++;

while (*s1 != '')
if (next == '' && mid == '-')
*s2++ = mid;
else if (mid == '-')
if (prev < next)
for (char i = prev; i <= next; i++, s2++)
*s2 = i;
else
for (char i = prev; i >= next; i--, s2++)
*s2 = i;

prev = *s1;
s1++;
mid = *s1;
if (*s1 != '')
next = *(s1 + 1);

*s2 = *s1;



What do you think about this solution? Does it solve the exercise? Is it a good way to solve it?







share|improve this question





















  • Well, you are writing in ANSI C, not K&R C. Your title reads “K&R C book”?
    – JDługosz
    Jun 9 at 22:28










  • They are probably reffering to the second edition. K&R C is named after the C shown in "The C Programming Language". The second edition is modified to use ANSI C.
    – Peter
    Jun 23 at 21:45










  • This is a terrible exercise. I don't understand the instructions at all. Does "be prepared to handle cases like a-b-c" mean the result would be abbc? or abc? And what does "Arrange that a leading or trailing -is taken literally." mean? Is it intended that when part of the string is not a range, that you simply copy it?
    – user1118321
    Jul 10 at 4:42












up vote
4
down vote

favorite









up vote
4
down vote

favorite











I have an exercise in my ANSI C book:




3.3. Write a function expand(s1,s2) that expands shorthand notations like a-z in the string s1 into the equivalent complete list abc…xyz in
s2. Allow for letters of either case and digits, and be prepared to
handle cases like a-b-c and a-z0-9 and -a-z. Arrange that a leading or
trailing - is taken literally.




I have attempted to solve it and here's my code:



#include <stdio.h>
#include <string.h>
#define MAXLEN 100

void expand(char * s1, char * s2);

int main(void)
char s1 = "a-b-c";
char s2[MAXLEN];
expand(s1, s2);
printf("%sn", s2);
return 0;


void expand(char * s1, char * s2)
char prev = '';
char mid = '';
char next = '';
if (s1[0] == '-')
*s2 = *s1;
s1++, s2++;

while (*s1 != '')
if (next == '' && mid == '-')
*s2++ = mid;
else if (mid == '-')
if (prev < next)
for (char i = prev; i <= next; i++, s2++)
*s2 = i;
else
for (char i = prev; i >= next; i--, s2++)
*s2 = i;

prev = *s1;
s1++;
mid = *s1;
if (*s1 != '')
next = *(s1 + 1);

*s2 = *s1;



What do you think about this solution? Does it solve the exercise? Is it a good way to solve it?







share|improve this question













I have an exercise in my ANSI C book:




3.3. Write a function expand(s1,s2) that expands shorthand notations like a-z in the string s1 into the equivalent complete list abc…xyz in
s2. Allow for letters of either case and digits, and be prepared to
handle cases like a-b-c and a-z0-9 and -a-z. Arrange that a leading or
trailing - is taken literally.




I have attempted to solve it and here's my code:



#include <stdio.h>
#include <string.h>
#define MAXLEN 100

void expand(char * s1, char * s2);

int main(void)
char s1 = "a-b-c";
char s2[MAXLEN];
expand(s1, s2);
printf("%sn", s2);
return 0;


void expand(char * s1, char * s2)
char prev = '';
char mid = '';
char next = '';
if (s1[0] == '-')
*s2 = *s1;
s1++, s2++;

while (*s1 != '')
if (next == '' && mid == '-')
*s2++ = mid;
else if (mid == '-')
if (prev < next)
for (char i = prev; i <= next; i++, s2++)
*s2 = i;
else
for (char i = prev; i >= next; i--, s2++)
*s2 = i;

prev = *s1;
s1++;
mid = *s1;
if (*s1 != '')
next = *(s1 + 1);

*s2 = *s1;



What do you think about this solution? Does it solve the exercise? Is it a good way to solve it?









share|improve this question












share|improve this question




share|improve this question








edited Jul 10 at 10:03









Toby Speight

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asked Jun 9 at 17:15









java-devel

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  • Well, you are writing in ANSI C, not K&R C. Your title reads “K&R C book”?
    – JDługosz
    Jun 9 at 22:28










  • They are probably reffering to the second edition. K&R C is named after the C shown in "The C Programming Language". The second edition is modified to use ANSI C.
    – Peter
    Jun 23 at 21:45










  • This is a terrible exercise. I don't understand the instructions at all. Does "be prepared to handle cases like a-b-c" mean the result would be abbc? or abc? And what does "Arrange that a leading or trailing -is taken literally." mean? Is it intended that when part of the string is not a range, that you simply copy it?
    – user1118321
    Jul 10 at 4:42
















  • Well, you are writing in ANSI C, not K&R C. Your title reads “K&R C book”?
    – JDługosz
    Jun 9 at 22:28










  • They are probably reffering to the second edition. K&R C is named after the C shown in "The C Programming Language". The second edition is modified to use ANSI C.
    – Peter
    Jun 23 at 21:45










  • This is a terrible exercise. I don't understand the instructions at all. Does "be prepared to handle cases like a-b-c" mean the result would be abbc? or abc? And what does "Arrange that a leading or trailing -is taken literally." mean? Is it intended that when part of the string is not a range, that you simply copy it?
    – user1118321
    Jul 10 at 4:42















Well, you are writing in ANSI C, not K&R C. Your title reads “K&R C book”?
– JDługosz
Jun 9 at 22:28




Well, you are writing in ANSI C, not K&R C. Your title reads “K&R C book”?
– JDługosz
Jun 9 at 22:28












They are probably reffering to the second edition. K&R C is named after the C shown in "The C Programming Language". The second edition is modified to use ANSI C.
– Peter
Jun 23 at 21:45




They are probably reffering to the second edition. K&R C is named after the C shown in "The C Programming Language". The second edition is modified to use ANSI C.
– Peter
Jun 23 at 21:45












This is a terrible exercise. I don't understand the instructions at all. Does "be prepared to handle cases like a-b-c" mean the result would be abbc? or abc? And what does "Arrange that a leading or trailing -is taken literally." mean? Is it intended that when part of the string is not a range, that you simply copy it?
– user1118321
Jul 10 at 4:42




This is a terrible exercise. I don't understand the instructions at all. Does "be prepared to handle cases like a-b-c" mean the result would be abbc? or abc? And what does "Arrange that a leading or trailing -is taken literally." mean? Is it intended that when part of the string is not a range, that you simply copy it?
– user1118321
Jul 10 at 4:42










2 Answers
2






active

oldest

votes

















up vote
1
down vote













#include <string.h>


We don't use any of the definitions of this header, so it can safely be omitted.




#define MAXLEN 100


Why 100? More importantly, what happens when we reach this maximum length? We probably need to add some code to stop producing output when it's reached. The provided interface expand(s1,s2) doesn't allow us to tell the function how much space is available to write into s2, so that's probably out of scope for the exercise, but consider implementing expand(s1,s2,max_len) as a further exercise (and a good one, that will be useful in your future C coding).




What should the output be for a-b-c? Your program produces abbc, but I don't know if that's expected. At least add a comment to document your assumptions. Other possible interpretations include abc and ab-c, so explain why you've chosen abbc for this input.




Another problematic test case: --5.




Use const for the input string. If we also return the start of the output, we can use the function more naturally:



char *expand(const char *s1, char *s2) 
char *const s2_start = s2;

/*...*/

return s2_start;


int main(void)
char s2[MAXLEN];
puts(expand("--5", s2));



Note that I've used puts() as a simpler alternative to sprintf("%sn", ).




Your indexing is odd and inconsistent. I see s1[0] mixed in with *s, and *(s1 + 1) in place of the simpler s1[1]. You can also make use of the value of increment expressions, like this:



if (*s1 == '-') 
*s2++ = *s1++;





 char i = prev;
if (prev < next)
while (i <= next)
*s2++ = i++;
else
while (i >= next)
*s2++ = i--;



Improved code



I've completely re-written, observing the above changes:



#include <stdio.h>

char *expand(const char *s1, char *s2, int max_len)
char *const s2_start = s2;
char *const s2_end = s2_start + max_len - 1;

while (*s1 && s2 < s2_end)
if (*s1 == '-' && s2 != s2_start && s1[1])
/* spotted hyphen not at beginning or end */
char first = s1[-1];
char last = *++s1;
/* produce a range first..last,
exclusive (we've already written first) */
if (first == last)
++s1;
else if (first < last)
/* ascending */
for (char i = ++first; i < last && s2 < s2_end; ++i)
*s2++ = i;
else
/* descending */
for (char i = --first; i > last && s2 < s2_end; --i)
*s2++ = i;

else
/* copy to output */
*s2++ = *s1++;


*s2 = '';

return s2_start;



#define MAXLEN 100
int main(void)
char s2[MAXLEN];
puts(expand("a-z-a-z-a", s2, MAXLEN));






share|improve this answer




























    up vote
    0
    down vote













    void expand(char * s1, char * s2);


    Although the placement of * (int * a or int* a or int *a), I would stick to one and only one throughout a codebase. Later on you have *s2 = *s1 so it's a good idea to use that style in the function signature as well.






    share|improve this answer

















    • 1




      But those are different cases. int * a is a parameter declaration, whereas *s1 = *s2; is an assignment. There's no reason you should expect them to be the same, in my opinion.
      – user1118321
      Jul 10 at 4:39










    • @user1118321 But they are not 'different cases'. The C syntax of type declaration is explained as mimicking the expression context: int *x declares the x identifier to provide int value if used in the *x expression. OTOH surrounding the asterisk with spaces suggests the multiplication operator, which is misleading here.
      – CiaPan
      Jul 10 at 10:32











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    2 Answers
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    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    1
    down vote













    #include <string.h>


    We don't use any of the definitions of this header, so it can safely be omitted.




    #define MAXLEN 100


    Why 100? More importantly, what happens when we reach this maximum length? We probably need to add some code to stop producing output when it's reached. The provided interface expand(s1,s2) doesn't allow us to tell the function how much space is available to write into s2, so that's probably out of scope for the exercise, but consider implementing expand(s1,s2,max_len) as a further exercise (and a good one, that will be useful in your future C coding).




    What should the output be for a-b-c? Your program produces abbc, but I don't know if that's expected. At least add a comment to document your assumptions. Other possible interpretations include abc and ab-c, so explain why you've chosen abbc for this input.




    Another problematic test case: --5.




    Use const for the input string. If we also return the start of the output, we can use the function more naturally:



    char *expand(const char *s1, char *s2) 
    char *const s2_start = s2;

    /*...*/

    return s2_start;


    int main(void)
    char s2[MAXLEN];
    puts(expand("--5", s2));



    Note that I've used puts() as a simpler alternative to sprintf("%sn", ).




    Your indexing is odd and inconsistent. I see s1[0] mixed in with *s, and *(s1 + 1) in place of the simpler s1[1]. You can also make use of the value of increment expressions, like this:



    if (*s1 == '-') 
    *s2++ = *s1++;





     char i = prev;
    if (prev < next)
    while (i <= next)
    *s2++ = i++;
    else
    while (i >= next)
    *s2++ = i--;



    Improved code



    I've completely re-written, observing the above changes:



    #include <stdio.h>

    char *expand(const char *s1, char *s2, int max_len)
    char *const s2_start = s2;
    char *const s2_end = s2_start + max_len - 1;

    while (*s1 && s2 < s2_end)
    if (*s1 == '-' && s2 != s2_start && s1[1])
    /* spotted hyphen not at beginning or end */
    char first = s1[-1];
    char last = *++s1;
    /* produce a range first..last,
    exclusive (we've already written first) */
    if (first == last)
    ++s1;
    else if (first < last)
    /* ascending */
    for (char i = ++first; i < last && s2 < s2_end; ++i)
    *s2++ = i;
    else
    /* descending */
    for (char i = --first; i > last && s2 < s2_end; --i)
    *s2++ = i;

    else
    /* copy to output */
    *s2++ = *s1++;


    *s2 = '';

    return s2_start;



    #define MAXLEN 100
    int main(void)
    char s2[MAXLEN];
    puts(expand("a-z-a-z-a", s2, MAXLEN));






    share|improve this answer

























      up vote
      1
      down vote













      #include <string.h>


      We don't use any of the definitions of this header, so it can safely be omitted.




      #define MAXLEN 100


      Why 100? More importantly, what happens when we reach this maximum length? We probably need to add some code to stop producing output when it's reached. The provided interface expand(s1,s2) doesn't allow us to tell the function how much space is available to write into s2, so that's probably out of scope for the exercise, but consider implementing expand(s1,s2,max_len) as a further exercise (and a good one, that will be useful in your future C coding).




      What should the output be for a-b-c? Your program produces abbc, but I don't know if that's expected. At least add a comment to document your assumptions. Other possible interpretations include abc and ab-c, so explain why you've chosen abbc for this input.




      Another problematic test case: --5.




      Use const for the input string. If we also return the start of the output, we can use the function more naturally:



      char *expand(const char *s1, char *s2) 
      char *const s2_start = s2;

      /*...*/

      return s2_start;


      int main(void)
      char s2[MAXLEN];
      puts(expand("--5", s2));



      Note that I've used puts() as a simpler alternative to sprintf("%sn", ).




      Your indexing is odd and inconsistent. I see s1[0] mixed in with *s, and *(s1 + 1) in place of the simpler s1[1]. You can also make use of the value of increment expressions, like this:



      if (*s1 == '-') 
      *s2++ = *s1++;





       char i = prev;
      if (prev < next)
      while (i <= next)
      *s2++ = i++;
      else
      while (i >= next)
      *s2++ = i--;



      Improved code



      I've completely re-written, observing the above changes:



      #include <stdio.h>

      char *expand(const char *s1, char *s2, int max_len)
      char *const s2_start = s2;
      char *const s2_end = s2_start + max_len - 1;

      while (*s1 && s2 < s2_end)
      if (*s1 == '-' && s2 != s2_start && s1[1])
      /* spotted hyphen not at beginning or end */
      char first = s1[-1];
      char last = *++s1;
      /* produce a range first..last,
      exclusive (we've already written first) */
      if (first == last)
      ++s1;
      else if (first < last)
      /* ascending */
      for (char i = ++first; i < last && s2 < s2_end; ++i)
      *s2++ = i;
      else
      /* descending */
      for (char i = --first; i > last && s2 < s2_end; --i)
      *s2++ = i;

      else
      /* copy to output */
      *s2++ = *s1++;


      *s2 = '';

      return s2_start;



      #define MAXLEN 100
      int main(void)
      char s2[MAXLEN];
      puts(expand("a-z-a-z-a", s2, MAXLEN));






      share|improve this answer























        up vote
        1
        down vote










        up vote
        1
        down vote









        #include <string.h>


        We don't use any of the definitions of this header, so it can safely be omitted.




        #define MAXLEN 100


        Why 100? More importantly, what happens when we reach this maximum length? We probably need to add some code to stop producing output when it's reached. The provided interface expand(s1,s2) doesn't allow us to tell the function how much space is available to write into s2, so that's probably out of scope for the exercise, but consider implementing expand(s1,s2,max_len) as a further exercise (and a good one, that will be useful in your future C coding).




        What should the output be for a-b-c? Your program produces abbc, but I don't know if that's expected. At least add a comment to document your assumptions. Other possible interpretations include abc and ab-c, so explain why you've chosen abbc for this input.




        Another problematic test case: --5.




        Use const for the input string. If we also return the start of the output, we can use the function more naturally:



        char *expand(const char *s1, char *s2) 
        char *const s2_start = s2;

        /*...*/

        return s2_start;


        int main(void)
        char s2[MAXLEN];
        puts(expand("--5", s2));



        Note that I've used puts() as a simpler alternative to sprintf("%sn", ).




        Your indexing is odd and inconsistent. I see s1[0] mixed in with *s, and *(s1 + 1) in place of the simpler s1[1]. You can also make use of the value of increment expressions, like this:



        if (*s1 == '-') 
        *s2++ = *s1++;





         char i = prev;
        if (prev < next)
        while (i <= next)
        *s2++ = i++;
        else
        while (i >= next)
        *s2++ = i--;



        Improved code



        I've completely re-written, observing the above changes:



        #include <stdio.h>

        char *expand(const char *s1, char *s2, int max_len)
        char *const s2_start = s2;
        char *const s2_end = s2_start + max_len - 1;

        while (*s1 && s2 < s2_end)
        if (*s1 == '-' && s2 != s2_start && s1[1])
        /* spotted hyphen not at beginning or end */
        char first = s1[-1];
        char last = *++s1;
        /* produce a range first..last,
        exclusive (we've already written first) */
        if (first == last)
        ++s1;
        else if (first < last)
        /* ascending */
        for (char i = ++first; i < last && s2 < s2_end; ++i)
        *s2++ = i;
        else
        /* descending */
        for (char i = --first; i > last && s2 < s2_end; --i)
        *s2++ = i;

        else
        /* copy to output */
        *s2++ = *s1++;


        *s2 = '';

        return s2_start;



        #define MAXLEN 100
        int main(void)
        char s2[MAXLEN];
        puts(expand("a-z-a-z-a", s2, MAXLEN));






        share|improve this answer













        #include <string.h>


        We don't use any of the definitions of this header, so it can safely be omitted.




        #define MAXLEN 100


        Why 100? More importantly, what happens when we reach this maximum length? We probably need to add some code to stop producing output when it's reached. The provided interface expand(s1,s2) doesn't allow us to tell the function how much space is available to write into s2, so that's probably out of scope for the exercise, but consider implementing expand(s1,s2,max_len) as a further exercise (and a good one, that will be useful in your future C coding).




        What should the output be for a-b-c? Your program produces abbc, but I don't know if that's expected. At least add a comment to document your assumptions. Other possible interpretations include abc and ab-c, so explain why you've chosen abbc for this input.




        Another problematic test case: --5.




        Use const for the input string. If we also return the start of the output, we can use the function more naturally:



        char *expand(const char *s1, char *s2) 
        char *const s2_start = s2;

        /*...*/

        return s2_start;


        int main(void)
        char s2[MAXLEN];
        puts(expand("--5", s2));



        Note that I've used puts() as a simpler alternative to sprintf("%sn", ).




        Your indexing is odd and inconsistent. I see s1[0] mixed in with *s, and *(s1 + 1) in place of the simpler s1[1]. You can also make use of the value of increment expressions, like this:



        if (*s1 == '-') 
        *s2++ = *s1++;





         char i = prev;
        if (prev < next)
        while (i <= next)
        *s2++ = i++;
        else
        while (i >= next)
        *s2++ = i--;



        Improved code



        I've completely re-written, observing the above changes:



        #include <stdio.h>

        char *expand(const char *s1, char *s2, int max_len)
        char *const s2_start = s2;
        char *const s2_end = s2_start + max_len - 1;

        while (*s1 && s2 < s2_end)
        if (*s1 == '-' && s2 != s2_start && s1[1])
        /* spotted hyphen not at beginning or end */
        char first = s1[-1];
        char last = *++s1;
        /* produce a range first..last,
        exclusive (we've already written first) */
        if (first == last)
        ++s1;
        else if (first < last)
        /* ascending */
        for (char i = ++first; i < last && s2 < s2_end; ++i)
        *s2++ = i;
        else
        /* descending */
        for (char i = --first; i > last && s2 < s2_end; --i)
        *s2++ = i;

        else
        /* copy to output */
        *s2++ = *s1++;


        *s2 = '';

        return s2_start;



        #define MAXLEN 100
        int main(void)
        char s2[MAXLEN];
        puts(expand("a-z-a-z-a", s2, MAXLEN));







        share|improve this answer













        share|improve this answer



        share|improve this answer











        answered Jul 10 at 10:50









        Toby Speight

        17.3k13487




        17.3k13487






















            up vote
            0
            down vote













            void expand(char * s1, char * s2);


            Although the placement of * (int * a or int* a or int *a), I would stick to one and only one throughout a codebase. Later on you have *s2 = *s1 so it's a good idea to use that style in the function signature as well.






            share|improve this answer

















            • 1




              But those are different cases. int * a is a parameter declaration, whereas *s1 = *s2; is an assignment. There's no reason you should expect them to be the same, in my opinion.
              – user1118321
              Jul 10 at 4:39










            • @user1118321 But they are not 'different cases'. The C syntax of type declaration is explained as mimicking the expression context: int *x declares the x identifier to provide int value if used in the *x expression. OTOH surrounding the asterisk with spaces suggests the multiplication operator, which is misleading here.
              – CiaPan
              Jul 10 at 10:32















            up vote
            0
            down vote













            void expand(char * s1, char * s2);


            Although the placement of * (int * a or int* a or int *a), I would stick to one and only one throughout a codebase. Later on you have *s2 = *s1 so it's a good idea to use that style in the function signature as well.






            share|improve this answer

















            • 1




              But those are different cases. int * a is a parameter declaration, whereas *s1 = *s2; is an assignment. There's no reason you should expect them to be the same, in my opinion.
              – user1118321
              Jul 10 at 4:39










            • @user1118321 But they are not 'different cases'. The C syntax of type declaration is explained as mimicking the expression context: int *x declares the x identifier to provide int value if used in the *x expression. OTOH surrounding the asterisk with spaces suggests the multiplication operator, which is misleading here.
              – CiaPan
              Jul 10 at 10:32













            up vote
            0
            down vote










            up vote
            0
            down vote









            void expand(char * s1, char * s2);


            Although the placement of * (int * a or int* a or int *a), I would stick to one and only one throughout a codebase. Later on you have *s2 = *s1 so it's a good idea to use that style in the function signature as well.






            share|improve this answer













            void expand(char * s1, char * s2);


            Although the placement of * (int * a or int* a or int *a), I would stick to one and only one throughout a codebase. Later on you have *s2 = *s1 so it's a good idea to use that style in the function signature as well.







            share|improve this answer













            share|improve this answer



            share|improve this answer











            answered Jun 9 at 22:29









            David Tran

            6113




            6113







            • 1




              But those are different cases. int * a is a parameter declaration, whereas *s1 = *s2; is an assignment. There's no reason you should expect them to be the same, in my opinion.
              – user1118321
              Jul 10 at 4:39










            • @user1118321 But they are not 'different cases'. The C syntax of type declaration is explained as mimicking the expression context: int *x declares the x identifier to provide int value if used in the *x expression. OTOH surrounding the asterisk with spaces suggests the multiplication operator, which is misleading here.
              – CiaPan
              Jul 10 at 10:32













            • 1




              But those are different cases. int * a is a parameter declaration, whereas *s1 = *s2; is an assignment. There's no reason you should expect them to be the same, in my opinion.
              – user1118321
              Jul 10 at 4:39










            • @user1118321 But they are not 'different cases'. The C syntax of type declaration is explained as mimicking the expression context: int *x declares the x identifier to provide int value if used in the *x expression. OTOH surrounding the asterisk with spaces suggests the multiplication operator, which is misleading here.
              – CiaPan
              Jul 10 at 10:32








            1




            1




            But those are different cases. int * a is a parameter declaration, whereas *s1 = *s2; is an assignment. There's no reason you should expect them to be the same, in my opinion.
            – user1118321
            Jul 10 at 4:39




            But those are different cases. int * a is a parameter declaration, whereas *s1 = *s2; is an assignment. There's no reason you should expect them to be the same, in my opinion.
            – user1118321
            Jul 10 at 4:39












            @user1118321 But they are not 'different cases'. The C syntax of type declaration is explained as mimicking the expression context: int *x declares the x identifier to provide int value if used in the *x expression. OTOH surrounding the asterisk with spaces suggests the multiplication operator, which is misleading here.
            – CiaPan
            Jul 10 at 10:32





            @user1118321 But they are not 'different cases'. The C syntax of type declaration is explained as mimicking the expression context: int *x declares the x identifier to provide int value if used in the *x expression. OTOH surrounding the asterisk with spaces suggests the multiplication operator, which is misleading here.
            – CiaPan
            Jul 10 at 10:32













             

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