Recursively check object for first array

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I am recursively checking an object to:

Find the largest JSON object

Find the array within it

It has to be rather flexible, as it should work with any structure of JSON data.

The below works, but it isn't flexible for all structures of JSON.

const data = foo: 1, bar: magic: , baz: woo: some: test: ['result'] 

const getField = (fields, item) => 
 if (fields.length < 1) 
 return item
 
 else 
 return fields.split('.').reduce((a, b) => a[b], item)
 


const checkObj = obj => Object.entries(obj).map(
 ([key, value]) => 
 return len: JSON.stringify(value).length, key: key, arr: Array.isArray(value) 
 
)

const findArr = obj => 
 let checked = ''
 let itm = checkObj(getField(checked, data))

 while (itm.some(e => !e.arr)) 
 itm = checkObj(getField(checked, data))
 const longestObj = itm.map(e => e).sort((a, b) => b.len - a.len)[0].key
 // Find longest key
 checked = checked.length > 1 ? `$checked.$longestObj` : longestObj
 // Track keys checked
 
 return checked
;

Test it out:
https://codesandbox.io/s/lr0ry18j2l

edited Apr 17 at 13:15

asked Apr 17 at 12:45

Ycon

1467

add a commentÂ |Â

up vote
0
down vote

favorite

I am recursively checking an object to:

Find the largest JSON object

Find the array within it

It has to be rather flexible, as it should work with any structure of JSON data.

The below works, but it isn't flexible for all structures of JSON.

const data = foo: 1, bar: magic: , baz: woo: some: test: ['result'] 

const getField = (fields, item) => 
 if (fields.length < 1) 
 return item
 
 else 
 return fields.split('.').reduce((a, b) => a[b], item)
 


const checkObj = obj => Object.entries(obj).map(
 ([key, value]) => 
 return len: JSON.stringify(value).length, key: key, arr: Array.isArray(value) 
 
)

const findArr = obj => 
 let checked = ''
 let itm = checkObj(getField(checked, data))

 while (itm.some(e => !e.arr)) 
 itm = checkObj(getField(checked, data))
 const longestObj = itm.map(e => e).sort((a, b) => b.len - a.len)[0].key
 // Find longest key
 checked = checked.length > 1 ? `$checked.$longestObj` : longestObj
 // Track keys checked
 
 return checked
;

Test it out:
https://codesandbox.io/s/lr0ry18j2l

edited Apr 17 at 13:15

asked Apr 17 at 12:45

Ycon

1467

add a commentÂ |Â

up vote
0
down vote

favorite

I am recursively checking an object to:

Find the largest JSON object

Find the array within it

It has to be rather flexible, as it should work with any structure of JSON data.

The below works, but it isn't flexible for all structures of JSON.

const data = foo: 1, bar: magic: , baz: woo: some: test: ['result'] 

const getField = (fields, item) => 
 if (fields.length < 1) 
 return item
 
 else 
 return fields.split('.').reduce((a, b) => a[b], item)
 


const checkObj = obj => Object.entries(obj).map(
 ([key, value]) => 
 return len: JSON.stringify(value).length, key: key, arr: Array.isArray(value) 
 
)

const findArr = obj => 
 let checked = ''
 let itm = checkObj(getField(checked, data))

 while (itm.some(e => !e.arr)) 
 itm = checkObj(getField(checked, data))
 const longestObj = itm.map(e => e).sort((a, b) => b.len - a.len)[0].key
 // Find longest key
 checked = checked.length > 1 ? `$checked.$longestObj` : longestObj
 // Track keys checked
 
 return checked
;

Test it out:
https://codesandbox.io/s/lr0ry18j2l

edited Apr 17 at 13:15

asked Apr 17 at 12:45

Ycon

1467

I am recursively checking an object to:

Find the largest JSON object

Find the array within it

It has to be rather flexible, as it should work with any structure of JSON data.

The below works, but it isn't flexible for all structures of JSON.

const data = foo: 1, bar: magic: , baz: woo: some: test: ['result'] 

const getField = (fields, item) => 
 if (fields.length < 1) 
 return item
 
 else 
 return fields.split('.').reduce((a, b) => a[b], item)
 


const checkObj = obj => Object.entries(obj).map(
 ([key, value]) => 
 return len: JSON.stringify(value).length, key: key, arr: Array.isArray(value) 
 
)

const findArr = obj => 
 let checked = ''
 let itm = checkObj(getField(checked, data))

 while (itm.some(e => !e.arr)) 
 itm = checkObj(getField(checked, data))
 const longestObj = itm.map(e => e).sort((a, b) => b.len - a.len)[0].key
 // Find longest key
 checked = checked.length > 1 ? `$checked.$longestObj` : longestObj
 // Track keys checked
 
 return checked
;

Test it out:
https://codesandbox.io/s/lr0ry18j2l

edited Apr 17 at 13:15

asked Apr 17 at 12:45

Ycon

1467

edited Apr 17 at 13:15

asked Apr 17 at 12:45

Ycon

1467

asked Apr 17 at 12:45

Ycon

1467

asked Apr 17 at 12:45

Ycon

1467

add a commentÂ |Â

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