trjhtr

I have a bidimensional array like this:

const bArray = 
[ [ 'Hello World',
 'Hi everybody',
 'How are you?'
 ],
 [ text: 'Hola Mundo',
 from: [Object],
 raw: '' ,
 text: 'Hola a todos',
 from: [Object],
 raw: '' ,
 text: 'Cómo estás?',
 from: [Object],
 raw: '' ,
 ]
]

And I need to get as a result, only one array that should look like this:

[
 en: 'Hello World',
 es: 'Hola Mundo' ,

 en: 'Hi everybody',
 es: 'Hola a todos' ,

 en: 'How are you?',
 es: 'Cómo estás?' ,
]

This is how I do it:

let val1 = bArray[0].map(tuple => tuple);
let val2 = bArray[1].map(tuple => tuple);

let result = val1.reduce((arr, v, i) => arr.concat("en" : v, "es" : val2[i].text), );

And now in the result variable, I have only one array with the result showed before.

My question?

Is there any improved way in which I can get the same result but with fewer lines of code? I mean, something like a combination of map with reduce, filter or concat in only one or two lines of code.

You can compact a lot into a single line, but that is most times not the best thing to do in both source code quality and execution efficiency.

const bArray = [['Hello World', 'Hi everybody', 'How are you?'], [ text: 'Hola Mundo', from: [Object], raw: '' , text: 'Hola a todos', from: [Object], raw: '' , text: 'Cómo estás?', from: [Object], raw: '' ,]];

const resultArray = bArray[0].reduce((arr, item, i) => (arr.push(en : item, es : bArray[1][i].text), arr), );
console.log(resultArray);

However I would do it as follows.

const bArray = [['Hello World', 'Hi everybody', 'How are you?'], [ text: 'Hola Mundo', from: [Object], raw: '' , text: 'Hola a todos', from: [Object], raw: '' , text: 'Cómo estás?', from: [Object], raw: '' ,] ];

const result = , aArr = bArray[0];
var i = 0;
for (const item of bArray[1]) result.push(es : item.text, en : aArr[i++]) 

console.log(result);

Which is easier to read and quicker when run.

Expanding it to idiomatic JS style.

const result = ;
let i = 0;
for (const en of bArray[0]) 
 result.push(
 en, 
 es : bArray[1][i++].text
 );


// or
const result = ;
let i = 0;
for (const item of bArray[1]) 
 result.push(
 es : item.text,
 en : bArray[0][i++]
 );