Linq IEnumerable extensions for void functions
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up vote
2
down vote
favorite
I found myself wanting to use Linq to map void methods to an IEnumerable to modify all items. The existing Linq methods require a return variable when mapping, since they are based on Func
.
So I decided to try my hand at creating some extension methods myself. This is the first time I've done anything like this, so if there are any pitfalls I'm missing, please do tell.
I created two extensions, one which applies a foreach loop to all elements, calling an Action<T>
for each. The second one is basically the Zip
extension, which allows for two IEnumerable
s to be iterated together and again maps a Action<T1,T2>
to both of them.
public static void ForEachAction<T>(this IEnumerable<T> sequence, Action<T> action)
foreach(T value in sequence)
action(value);
public static void ForEachActionZip<Tbase, Tsecond>(this IEnumerable<Tbase> sequence, IEnumerable<Tsecond> second, Action<Tbase, Tsecond> action)
sequence.Zip(second, (first, other) => new first, other ).ForEachAction(x => action(x.first, x.other));
You can then use this like so:
someList.ForEachAction(x => x.Update());
or
someList.ForEachActionZip(secondList, (a, b) => a.Update(b));
c# linq
add a comment |Â
up vote
2
down vote
favorite
I found myself wanting to use Linq to map void methods to an IEnumerable to modify all items. The existing Linq methods require a return variable when mapping, since they are based on Func
.
So I decided to try my hand at creating some extension methods myself. This is the first time I've done anything like this, so if there are any pitfalls I'm missing, please do tell.
I created two extensions, one which applies a foreach loop to all elements, calling an Action<T>
for each. The second one is basically the Zip
extension, which allows for two IEnumerable
s to be iterated together and again maps a Action<T1,T2>
to both of them.
public static void ForEachAction<T>(this IEnumerable<T> sequence, Action<T> action)
foreach(T value in sequence)
action(value);
public static void ForEachActionZip<Tbase, Tsecond>(this IEnumerable<Tbase> sequence, IEnumerable<Tsecond> second, Action<Tbase, Tsecond> action)
sequence.Zip(second, (first, other) => new first, other ).ForEachAction(x => action(x.first, x.other));
You can then use this like so:
someList.ForEachAction(x => x.Update());
or
someList.ForEachActionZip(secondList, (a, b) => a.Update(b));
c# linq
1
Are you sure you want to mix functional programming with side effects? Why not use aforeach
loop instead?
â Pieter Witvoet
Mar 23 at 14:11
@PieterWitvoet If I have two enumerables and I want to map some method with side-effects to both, using a foreach loop is kind of a pain. I don't really see a straightforward way to accomplish that.
â JAD
Mar 23 at 14:20
1
What aboutforeach (var item in first.Zip(second, ...))
, where...
could produce a (value) tuple or an object of an existing or anonymous type? If used a lot, you could write aZip
extension method that doesn't require aFunc<>
argument. If it returned a value tuple, you could writeforeach (var (item1, item2) in first.Zip(second))
.
â Pieter Witvoet
Mar 23 at 14:51
add a comment |Â
up vote
2
down vote
favorite
up vote
2
down vote
favorite
I found myself wanting to use Linq to map void methods to an IEnumerable to modify all items. The existing Linq methods require a return variable when mapping, since they are based on Func
.
So I decided to try my hand at creating some extension methods myself. This is the first time I've done anything like this, so if there are any pitfalls I'm missing, please do tell.
I created two extensions, one which applies a foreach loop to all elements, calling an Action<T>
for each. The second one is basically the Zip
extension, which allows for two IEnumerable
s to be iterated together and again maps a Action<T1,T2>
to both of them.
public static void ForEachAction<T>(this IEnumerable<T> sequence, Action<T> action)
foreach(T value in sequence)
action(value);
public static void ForEachActionZip<Tbase, Tsecond>(this IEnumerable<Tbase> sequence, IEnumerable<Tsecond> second, Action<Tbase, Tsecond> action)
sequence.Zip(second, (first, other) => new first, other ).ForEachAction(x => action(x.first, x.other));
You can then use this like so:
someList.ForEachAction(x => x.Update());
or
someList.ForEachActionZip(secondList, (a, b) => a.Update(b));
c# linq
I found myself wanting to use Linq to map void methods to an IEnumerable to modify all items. The existing Linq methods require a return variable when mapping, since they are based on Func
.
So I decided to try my hand at creating some extension methods myself. This is the first time I've done anything like this, so if there are any pitfalls I'm missing, please do tell.
I created two extensions, one which applies a foreach loop to all elements, calling an Action<T>
for each. The second one is basically the Zip
extension, which allows for two IEnumerable
s to be iterated together and again maps a Action<T1,T2>
to both of them.
public static void ForEachAction<T>(this IEnumerable<T> sequence, Action<T> action)
foreach(T value in sequence)
action(value);
public static void ForEachActionZip<Tbase, Tsecond>(this IEnumerable<Tbase> sequence, IEnumerable<Tsecond> second, Action<Tbase, Tsecond> action)
sequence.Zip(second, (first, other) => new first, other ).ForEachAction(x => action(x.first, x.other));
You can then use this like so:
someList.ForEachAction(x => x.Update());
or
someList.ForEachActionZip(secondList, (a, b) => a.Update(b));
c# linq
asked Mar 23 at 13:19
JAD
502317
502317
1
Are you sure you want to mix functional programming with side effects? Why not use aforeach
loop instead?
â Pieter Witvoet
Mar 23 at 14:11
@PieterWitvoet If I have two enumerables and I want to map some method with side-effects to both, using a foreach loop is kind of a pain. I don't really see a straightforward way to accomplish that.
â JAD
Mar 23 at 14:20
1
What aboutforeach (var item in first.Zip(second, ...))
, where...
could produce a (value) tuple or an object of an existing or anonymous type? If used a lot, you could write aZip
extension method that doesn't require aFunc<>
argument. If it returned a value tuple, you could writeforeach (var (item1, item2) in first.Zip(second))
.
â Pieter Witvoet
Mar 23 at 14:51
add a comment |Â
1
Are you sure you want to mix functional programming with side effects? Why not use aforeach
loop instead?
â Pieter Witvoet
Mar 23 at 14:11
@PieterWitvoet If I have two enumerables and I want to map some method with side-effects to both, using a foreach loop is kind of a pain. I don't really see a straightforward way to accomplish that.
â JAD
Mar 23 at 14:20
1
What aboutforeach (var item in first.Zip(second, ...))
, where...
could produce a (value) tuple or an object of an existing or anonymous type? If used a lot, you could write aZip
extension method that doesn't require aFunc<>
argument. If it returned a value tuple, you could writeforeach (var (item1, item2) in first.Zip(second))
.
â Pieter Witvoet
Mar 23 at 14:51
1
1
Are you sure you want to mix functional programming with side effects? Why not use a
foreach
loop instead?â Pieter Witvoet
Mar 23 at 14:11
Are you sure you want to mix functional programming with side effects? Why not use a
foreach
loop instead?â Pieter Witvoet
Mar 23 at 14:11
@PieterWitvoet If I have two enumerables and I want to map some method with side-effects to both, using a foreach loop is kind of a pain. I don't really see a straightforward way to accomplish that.
â JAD
Mar 23 at 14:20
@PieterWitvoet If I have two enumerables and I want to map some method with side-effects to both, using a foreach loop is kind of a pain. I don't really see a straightforward way to accomplish that.
â JAD
Mar 23 at 14:20
1
1
What about
foreach (var item in first.Zip(second, ...))
, where ...
could produce a (value) tuple or an object of an existing or anonymous type? If used a lot, you could write a Zip
extension method that doesn't require a Func<>
argument. If it returned a value tuple, you could write foreach (var (item1, item2) in first.Zip(second))
.â Pieter Witvoet
Mar 23 at 14:51
What about
foreach (var item in first.Zip(second, ...))
, where ...
could produce a (value) tuple or an object of an existing or anonymous type? If used a lot, you could write a Zip
extension method that doesn't require a Func<>
argument. If it returned a value tuple, you could write foreach (var (item1, item2) in first.Zip(second))
.â Pieter Witvoet
Mar 23 at 14:51
add a comment |Â
2 Answers
2
active
oldest
votes
up vote
8
down vote
This is generally considered to be a bad idea. IEnumerable
has deferred execution, which means that in your example, someList
can be forced to enumerate any desired number of times.
As a consequence, it depends on the implementation behind the IEnumerable
whether any changes applied by action
will still be visible after your methods have run. There are two possibilities:
someList
is a materialized list (for example,List<SomeObject>
). After runningForEachAction
, a new enumeration ofsomeList
will produce the same, modified, objects.someList
is an enumerable that produces new objects on each execution. After runningForEachAction
, a new enumeration ofsomeList
will produce new objects. The changed objects are out of scope and will soon be garbage collected.
An example of the second option is an IQueryable
against a SQL backend. When it is executed it will emit a SQL query that returns new objects from the database (caching as applied by many ORMs aside).
In that case it totally depends on what happens in action
whether any effect of it is persistent. If action
only modifies objects in someList
its effect will be lost. If it uses objects in someList
to change some external state (e.g. increment some sum value) its effect will persist.
As a conclusion, I wouldn't do this. If you want to apply void methods to any IEnumerable
, first materialize it to a list and then apply existing methods. Instead of...
someList.ForEachAction(x => x.Update());
...you'd have...
var concreteList = someList.ToList();
concreteList.ForEach(x => x.Update());
Now continue working with concreteList
so you'll be sure that the effect of x.Update()
will remain visible in your code.
I think this will only be usable for reference types. For value types the items in concreteList will still remain unchanged.
â Henrik Hansen
Mar 23 at 15:17
@HenrikHansen But they probably won't try to modify value types. Anyway, as I said, this approach makes the effect dependent of what happens in the action, making it unpredictable as a whole.
â Gert Arnold
Mar 23 at 15:25
Your point in point 1 is that if I have say two expressions with the same enumerable, with the second one having side-effects like this, the first one could be deferred until after the second one executed, causing it to enumerate with the modified objects. Is that correct? If so, is that truly different with the.ForEach
method?
â JAD
Mar 23 at 20:00
I'm not sure if I understand what you're asking, but the power of LINQ operations is that they can be chained without ever being executed. Only if in the end execution is forced by an immediately executing operation --likeToList
,First
, orSum
-- will the whole pipeline be enumerated. The whole point of my answer is: if you change state of objects produced by anyIEnumerable
(chained or not) you must make sure that you store these objects locally.
â Gert Arnold
Mar 24 at 10:22
@GertArnold But the intention for these methods is specifically to act as those immediately executing operations. They return void after all. As far as I am aware, theforeach
loop inForEachAction
should force the enumerable to enumerate right?
â JAD
Mar 28 at 20:46
 |Â
show 2 more comments
up vote
2
down vote
If you want them to act a bit more like the Microsoft-supplied LINQ extension methods, you may want to consider some parameter checks (for example):
public static void ForEachAction<T>(this IEnumerable<T> sequence, Action<T> action)
if (sequence== null)
throw new ArgumentNullException(nameof(sequence));
if (action== null)
throw new ArgumentNullException(nameof(action));
sequence.ForEachActionInternal(action);
private static void ForEachActionInternal<T>(this IEnumerable<T> sequence, Action<T> action)
foreach(T value in sequence)
action(value);
I've split it into two methods in case you decide to have your methods return a sequence of some sort lazily.
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
8
down vote
This is generally considered to be a bad idea. IEnumerable
has deferred execution, which means that in your example, someList
can be forced to enumerate any desired number of times.
As a consequence, it depends on the implementation behind the IEnumerable
whether any changes applied by action
will still be visible after your methods have run. There are two possibilities:
someList
is a materialized list (for example,List<SomeObject>
). After runningForEachAction
, a new enumeration ofsomeList
will produce the same, modified, objects.someList
is an enumerable that produces new objects on each execution. After runningForEachAction
, a new enumeration ofsomeList
will produce new objects. The changed objects are out of scope and will soon be garbage collected.
An example of the second option is an IQueryable
against a SQL backend. When it is executed it will emit a SQL query that returns new objects from the database (caching as applied by many ORMs aside).
In that case it totally depends on what happens in action
whether any effect of it is persistent. If action
only modifies objects in someList
its effect will be lost. If it uses objects in someList
to change some external state (e.g. increment some sum value) its effect will persist.
As a conclusion, I wouldn't do this. If you want to apply void methods to any IEnumerable
, first materialize it to a list and then apply existing methods. Instead of...
someList.ForEachAction(x => x.Update());
...you'd have...
var concreteList = someList.ToList();
concreteList.ForEach(x => x.Update());
Now continue working with concreteList
so you'll be sure that the effect of x.Update()
will remain visible in your code.
I think this will only be usable for reference types. For value types the items in concreteList will still remain unchanged.
â Henrik Hansen
Mar 23 at 15:17
@HenrikHansen But they probably won't try to modify value types. Anyway, as I said, this approach makes the effect dependent of what happens in the action, making it unpredictable as a whole.
â Gert Arnold
Mar 23 at 15:25
Your point in point 1 is that if I have say two expressions with the same enumerable, with the second one having side-effects like this, the first one could be deferred until after the second one executed, causing it to enumerate with the modified objects. Is that correct? If so, is that truly different with the.ForEach
method?
â JAD
Mar 23 at 20:00
I'm not sure if I understand what you're asking, but the power of LINQ operations is that they can be chained without ever being executed. Only if in the end execution is forced by an immediately executing operation --likeToList
,First
, orSum
-- will the whole pipeline be enumerated. The whole point of my answer is: if you change state of objects produced by anyIEnumerable
(chained or not) you must make sure that you store these objects locally.
â Gert Arnold
Mar 24 at 10:22
@GertArnold But the intention for these methods is specifically to act as those immediately executing operations. They return void after all. As far as I am aware, theforeach
loop inForEachAction
should force the enumerable to enumerate right?
â JAD
Mar 28 at 20:46
 |Â
show 2 more comments
up vote
8
down vote
This is generally considered to be a bad idea. IEnumerable
has deferred execution, which means that in your example, someList
can be forced to enumerate any desired number of times.
As a consequence, it depends on the implementation behind the IEnumerable
whether any changes applied by action
will still be visible after your methods have run. There are two possibilities:
someList
is a materialized list (for example,List<SomeObject>
). After runningForEachAction
, a new enumeration ofsomeList
will produce the same, modified, objects.someList
is an enumerable that produces new objects on each execution. After runningForEachAction
, a new enumeration ofsomeList
will produce new objects. The changed objects are out of scope and will soon be garbage collected.
An example of the second option is an IQueryable
against a SQL backend. When it is executed it will emit a SQL query that returns new objects from the database (caching as applied by many ORMs aside).
In that case it totally depends on what happens in action
whether any effect of it is persistent. If action
only modifies objects in someList
its effect will be lost. If it uses objects in someList
to change some external state (e.g. increment some sum value) its effect will persist.
As a conclusion, I wouldn't do this. If you want to apply void methods to any IEnumerable
, first materialize it to a list and then apply existing methods. Instead of...
someList.ForEachAction(x => x.Update());
...you'd have...
var concreteList = someList.ToList();
concreteList.ForEach(x => x.Update());
Now continue working with concreteList
so you'll be sure that the effect of x.Update()
will remain visible in your code.
I think this will only be usable for reference types. For value types the items in concreteList will still remain unchanged.
â Henrik Hansen
Mar 23 at 15:17
@HenrikHansen But they probably won't try to modify value types. Anyway, as I said, this approach makes the effect dependent of what happens in the action, making it unpredictable as a whole.
â Gert Arnold
Mar 23 at 15:25
Your point in point 1 is that if I have say two expressions with the same enumerable, with the second one having side-effects like this, the first one could be deferred until after the second one executed, causing it to enumerate with the modified objects. Is that correct? If so, is that truly different with the.ForEach
method?
â JAD
Mar 23 at 20:00
I'm not sure if I understand what you're asking, but the power of LINQ operations is that they can be chained without ever being executed. Only if in the end execution is forced by an immediately executing operation --likeToList
,First
, orSum
-- will the whole pipeline be enumerated. The whole point of my answer is: if you change state of objects produced by anyIEnumerable
(chained or not) you must make sure that you store these objects locally.
â Gert Arnold
Mar 24 at 10:22
@GertArnold But the intention for these methods is specifically to act as those immediately executing operations. They return void after all. As far as I am aware, theforeach
loop inForEachAction
should force the enumerable to enumerate right?
â JAD
Mar 28 at 20:46
 |Â
show 2 more comments
up vote
8
down vote
up vote
8
down vote
This is generally considered to be a bad idea. IEnumerable
has deferred execution, which means that in your example, someList
can be forced to enumerate any desired number of times.
As a consequence, it depends on the implementation behind the IEnumerable
whether any changes applied by action
will still be visible after your methods have run. There are two possibilities:
someList
is a materialized list (for example,List<SomeObject>
). After runningForEachAction
, a new enumeration ofsomeList
will produce the same, modified, objects.someList
is an enumerable that produces new objects on each execution. After runningForEachAction
, a new enumeration ofsomeList
will produce new objects. The changed objects are out of scope and will soon be garbage collected.
An example of the second option is an IQueryable
against a SQL backend. When it is executed it will emit a SQL query that returns new objects from the database (caching as applied by many ORMs aside).
In that case it totally depends on what happens in action
whether any effect of it is persistent. If action
only modifies objects in someList
its effect will be lost. If it uses objects in someList
to change some external state (e.g. increment some sum value) its effect will persist.
As a conclusion, I wouldn't do this. If you want to apply void methods to any IEnumerable
, first materialize it to a list and then apply existing methods. Instead of...
someList.ForEachAction(x => x.Update());
...you'd have...
var concreteList = someList.ToList();
concreteList.ForEach(x => x.Update());
Now continue working with concreteList
so you'll be sure that the effect of x.Update()
will remain visible in your code.
This is generally considered to be a bad idea. IEnumerable
has deferred execution, which means that in your example, someList
can be forced to enumerate any desired number of times.
As a consequence, it depends on the implementation behind the IEnumerable
whether any changes applied by action
will still be visible after your methods have run. There are two possibilities:
someList
is a materialized list (for example,List<SomeObject>
). After runningForEachAction
, a new enumeration ofsomeList
will produce the same, modified, objects.someList
is an enumerable that produces new objects on each execution. After runningForEachAction
, a new enumeration ofsomeList
will produce new objects. The changed objects are out of scope and will soon be garbage collected.
An example of the second option is an IQueryable
against a SQL backend. When it is executed it will emit a SQL query that returns new objects from the database (caching as applied by many ORMs aside).
In that case it totally depends on what happens in action
whether any effect of it is persistent. If action
only modifies objects in someList
its effect will be lost. If it uses objects in someList
to change some external state (e.g. increment some sum value) its effect will persist.
As a conclusion, I wouldn't do this. If you want to apply void methods to any IEnumerable
, first materialize it to a list and then apply existing methods. Instead of...
someList.ForEachAction(x => x.Update());
...you'd have...
var concreteList = someList.ToList();
concreteList.ForEach(x => x.Update());
Now continue working with concreteList
so you'll be sure that the effect of x.Update()
will remain visible in your code.
edited Mar 28 at 20:52
answered Mar 23 at 14:41
Gert Arnold
1,37211120
1,37211120
I think this will only be usable for reference types. For value types the items in concreteList will still remain unchanged.
â Henrik Hansen
Mar 23 at 15:17
@HenrikHansen But they probably won't try to modify value types. Anyway, as I said, this approach makes the effect dependent of what happens in the action, making it unpredictable as a whole.
â Gert Arnold
Mar 23 at 15:25
Your point in point 1 is that if I have say two expressions with the same enumerable, with the second one having side-effects like this, the first one could be deferred until after the second one executed, causing it to enumerate with the modified objects. Is that correct? If so, is that truly different with the.ForEach
method?
â JAD
Mar 23 at 20:00
I'm not sure if I understand what you're asking, but the power of LINQ operations is that they can be chained without ever being executed. Only if in the end execution is forced by an immediately executing operation --likeToList
,First
, orSum
-- will the whole pipeline be enumerated. The whole point of my answer is: if you change state of objects produced by anyIEnumerable
(chained or not) you must make sure that you store these objects locally.
â Gert Arnold
Mar 24 at 10:22
@GertArnold But the intention for these methods is specifically to act as those immediately executing operations. They return void after all. As far as I am aware, theforeach
loop inForEachAction
should force the enumerable to enumerate right?
â JAD
Mar 28 at 20:46
 |Â
show 2 more comments
I think this will only be usable for reference types. For value types the items in concreteList will still remain unchanged.
â Henrik Hansen
Mar 23 at 15:17
@HenrikHansen But they probably won't try to modify value types. Anyway, as I said, this approach makes the effect dependent of what happens in the action, making it unpredictable as a whole.
â Gert Arnold
Mar 23 at 15:25
Your point in point 1 is that if I have say two expressions with the same enumerable, with the second one having side-effects like this, the first one could be deferred until after the second one executed, causing it to enumerate with the modified objects. Is that correct? If so, is that truly different with the.ForEach
method?
â JAD
Mar 23 at 20:00
I'm not sure if I understand what you're asking, but the power of LINQ operations is that they can be chained without ever being executed. Only if in the end execution is forced by an immediately executing operation --likeToList
,First
, orSum
-- will the whole pipeline be enumerated. The whole point of my answer is: if you change state of objects produced by anyIEnumerable
(chained or not) you must make sure that you store these objects locally.
â Gert Arnold
Mar 24 at 10:22
@GertArnold But the intention for these methods is specifically to act as those immediately executing operations. They return void after all. As far as I am aware, theforeach
loop inForEachAction
should force the enumerable to enumerate right?
â JAD
Mar 28 at 20:46
I think this will only be usable for reference types. For value types the items in concreteList will still remain unchanged.
â Henrik Hansen
Mar 23 at 15:17
I think this will only be usable for reference types. For value types the items in concreteList will still remain unchanged.
â Henrik Hansen
Mar 23 at 15:17
@HenrikHansen But they probably won't try to modify value types. Anyway, as I said, this approach makes the effect dependent of what happens in the action, making it unpredictable as a whole.
â Gert Arnold
Mar 23 at 15:25
@HenrikHansen But they probably won't try to modify value types. Anyway, as I said, this approach makes the effect dependent of what happens in the action, making it unpredictable as a whole.
â Gert Arnold
Mar 23 at 15:25
Your point in point 1 is that if I have say two expressions with the same enumerable, with the second one having side-effects like this, the first one could be deferred until after the second one executed, causing it to enumerate with the modified objects. Is that correct? If so, is that truly different with the
.ForEach
method?â JAD
Mar 23 at 20:00
Your point in point 1 is that if I have say two expressions with the same enumerable, with the second one having side-effects like this, the first one could be deferred until after the second one executed, causing it to enumerate with the modified objects. Is that correct? If so, is that truly different with the
.ForEach
method?â JAD
Mar 23 at 20:00
I'm not sure if I understand what you're asking, but the power of LINQ operations is that they can be chained without ever being executed. Only if in the end execution is forced by an immediately executing operation --like
ToList
, First
, or Sum
-- will the whole pipeline be enumerated. The whole point of my answer is: if you change state of objects produced by any IEnumerable
(chained or not) you must make sure that you store these objects locally.â Gert Arnold
Mar 24 at 10:22
I'm not sure if I understand what you're asking, but the power of LINQ operations is that they can be chained without ever being executed. Only if in the end execution is forced by an immediately executing operation --like
ToList
, First
, or Sum
-- will the whole pipeline be enumerated. The whole point of my answer is: if you change state of objects produced by any IEnumerable
(chained or not) you must make sure that you store these objects locally.â Gert Arnold
Mar 24 at 10:22
@GertArnold But the intention for these methods is specifically to act as those immediately executing operations. They return void after all. As far as I am aware, the
foreach
loop in ForEachAction
should force the enumerable to enumerate right?â JAD
Mar 28 at 20:46
@GertArnold But the intention for these methods is specifically to act as those immediately executing operations. They return void after all. As far as I am aware, the
foreach
loop in ForEachAction
should force the enumerable to enumerate right?â JAD
Mar 28 at 20:46
 |Â
show 2 more comments
up vote
2
down vote
If you want them to act a bit more like the Microsoft-supplied LINQ extension methods, you may want to consider some parameter checks (for example):
public static void ForEachAction<T>(this IEnumerable<T> sequence, Action<T> action)
if (sequence== null)
throw new ArgumentNullException(nameof(sequence));
if (action== null)
throw new ArgumentNullException(nameof(action));
sequence.ForEachActionInternal(action);
private static void ForEachActionInternal<T>(this IEnumerable<T> sequence, Action<T> action)
foreach(T value in sequence)
action(value);
I've split it into two methods in case you decide to have your methods return a sequence of some sort lazily.
add a comment |Â
up vote
2
down vote
If you want them to act a bit more like the Microsoft-supplied LINQ extension methods, you may want to consider some parameter checks (for example):
public static void ForEachAction<T>(this IEnumerable<T> sequence, Action<T> action)
if (sequence== null)
throw new ArgumentNullException(nameof(sequence));
if (action== null)
throw new ArgumentNullException(nameof(action));
sequence.ForEachActionInternal(action);
private static void ForEachActionInternal<T>(this IEnumerable<T> sequence, Action<T> action)
foreach(T value in sequence)
action(value);
I've split it into two methods in case you decide to have your methods return a sequence of some sort lazily.
add a comment |Â
up vote
2
down vote
up vote
2
down vote
If you want them to act a bit more like the Microsoft-supplied LINQ extension methods, you may want to consider some parameter checks (for example):
public static void ForEachAction<T>(this IEnumerable<T> sequence, Action<T> action)
if (sequence== null)
throw new ArgumentNullException(nameof(sequence));
if (action== null)
throw new ArgumentNullException(nameof(action));
sequence.ForEachActionInternal(action);
private static void ForEachActionInternal<T>(this IEnumerable<T> sequence, Action<T> action)
foreach(T value in sequence)
action(value);
I've split it into two methods in case you decide to have your methods return a sequence of some sort lazily.
If you want them to act a bit more like the Microsoft-supplied LINQ extension methods, you may want to consider some parameter checks (for example):
public static void ForEachAction<T>(this IEnumerable<T> sequence, Action<T> action)
if (sequence== null)
throw new ArgumentNullException(nameof(sequence));
if (action== null)
throw new ArgumentNullException(nameof(action));
sequence.ForEachActionInternal(action);
private static void ForEachActionInternal<T>(this IEnumerable<T> sequence, Action<T> action)
foreach(T value in sequence)
action(value);
I've split it into two methods in case you decide to have your methods return a sequence of some sort lazily.
answered Mar 23 at 13:47
Jesse C. Slicer
10.9k2738
10.9k2738
add a comment |Â
add a comment |Â
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1
Are you sure you want to mix functional programming with side effects? Why not use a
foreach
loop instead?â Pieter Witvoet
Mar 23 at 14:11
@PieterWitvoet If I have two enumerables and I want to map some method with side-effects to both, using a foreach loop is kind of a pain. I don't really see a straightforward way to accomplish that.
â JAD
Mar 23 at 14:20
1
What about
foreach (var item in first.Zip(second, ...))
, where...
could produce a (value) tuple or an object of an existing or anonymous type? If used a lot, you could write aZip
extension method that doesn't require aFunc<>
argument. If it returned a value tuple, you could writeforeach (var (item1, item2) in first.Zip(second))
.â Pieter Witvoet
Mar 23 at 14:51